JEE Main202125 Jul 2021Evening ShiftPhysicsCapacitanceActual
If q f is the free charge on the capacitor plates and q b is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then bound charge q b can be expressed as :
Options
- Aq b = q f 1 - 1 k
- Bq b = q i 1 - 1 k
- Cq b = q f 1 + 1 k
- Dq b = q f 1 + 1 k
Correct answer
B. q b = q i 1 - 1 k
Step-by-step solution
When a dielectric is inserted in a capacitor, q b = q i 1 - 1 k