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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2023 · 15 April · Morning Shift · Physics · Rotational Motion

A solid sphere and a solid cylinder of same mass and radius are...

A solid sphere and a solid cylinder of same mass and radius are rolling on a horizontal surface without slipping. The ratio of their radius of gyrations respectively (ksph:kcyl)\left({k}_{sph}: {k}_{cyl}\right) is 2:x2: \sqrt{x}. The value of xx is _______.

Correct answer

0

Step-by-step solution

Considering rotational axis as the diametrical axis for sphere and axis of cylinder. Then

K12=25R2{K}_{1}^{2} = \dfrac{2}{5}{R}^{2} and K22=12R2{K}_{2}^{2} = \dfrac{1}{2}{R}^{2}

∴K1K2=2/51/2=45∴ \dfrac{{K}_{1}}{{K}_{2}} = \sqrt{\dfrac{2 / 5}{1 / 2}} = \sqrt{\dfrac{4}{5}}

⇒K1K2=25⇒ \dfrac{{K}_{1}}{{K}_{2}} = \dfrac{2}{\sqrt{5}}

Comparing it with the given value in the question,

25=2x\dfrac{2}{\sqrt{5}} = \dfrac{2}{\sqrt{x}}

∴∴ x=5x = 5

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