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JEE Main202313 Apr 2023Evening ShiftPhysicsRotational MotionActual

A light rope is wound around a hollow cylinder of mass 5 kg and radius 70 cm . The rope is pulled with a force of 52 . 5 N . The angular acceleration of the cylinder will be _____ rad s - 2 .

Correct answer

0

Step-by-step solution

The formula to calculate the moment of inertia I of the cylinder about its radial axis is given by I = M r 2       . . . 1 Also, the torque τ on the cylinder about the central axis because of the application of the external force is given by τ =   F r       . . . 2 Also, the torque can be expressed as τ = I α       . . . 3 Substitute the expressions from equation (1) and (2) into equation (3) and simplify to obtain the angular acceleration. F r =

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