The moment of inertia of a semicircular ring about a line perpendicular to the plane of the ring and passing through its centre is given as $I$ $= M{R}^{2}$ , where $m$ and $R$ are the mass and radius of the ring. Comparing the given value
. $I = {MR}^{2} = \dfrac{1}{x}M{R}^{2}$
$⇒ x = 1$

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The moment of inertia of a semicircular ring about a line perpendicular to the plane of the ring and passing through its centre is given as $I$ $= M{R}^{2}$ , where $m$ and $R$ are the mass and radius of the ring. Comparing the given value
. $I = {MR}^{2} = \dfrac{1}{x}M{R}^{2}$
$⇒ x = 1$

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The moment of inertia of a semicircular ring about a line perpendicular to the plane of the ring and passing through its centre is given as $I$ $= M{R}^{2}$ , where $m$ and $R$ are the mass and radius of the ring. Comparing the given value
. $I = {MR}^{2} = \dfrac{1}{x}M{R}^{2}$
$⇒ x = 1$

The moment of inertia of a semicircular ring about an axis, passing...

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