The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1 x MR 2 , where R is the radius and M is the mass of the semicircular ring. The value of x will be _ _ _ _ _ _ _ .

Step-by-step solution

The moment of inertia of a semicircular ring about a line perpendicular to the plane of the ring and passing through its centre is given as  I = M R 2 , where m and   R are the mass and radius of the ring. Comparing the given value . I =   MR 2 = 1 x M R 2 ⇒ x = 1