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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Chemistry
Chapter
Coordination Compounds

JIPMER 2018 · Chemistry · Coordination Compounds

Which one of the following species is paramagnetic in nature?

Which one of the following species is paramagnetic in nature?

Options

  1. AV4+\mathrm{V}^{4+}
  2. BSc3+\mathrm{Sc}^{3+}
  3. CV5+V^{5+}
  4. DZn2+\mathrm{Zn}^{2+}

Correct answer

A. V4+\mathrm{V}^{4+}

Step-by-step solution

The number of unpaired electrons and electronic configuration of the given species is shown below - V4+[Z=23]=[Ar]183 d1\mathrm{V}^{4+}[\mathrm{Z}=23]=[\mathrm{Ar}]_{18} 3 \mathrm{~d}^1 No. of unpaired electron =1=1 - Sc3+[Z=2l]=[Ar]183 d0\mathrm{Sc}^{3+}[\mathrm{Z}=2 \mathrm{l}]=[\mathrm{Ar}]_{18} 3 \mathrm{~d}^0 No. of unpaired electron =0=0 - V5+[Z=23]=[Ar]183 d0\mathrm{V}^{5+}[\mathrm{Z}=23]=[\mathrm{Ar}]_{18} 3 \mathrm{~d}^0 No. of unpaired electron =0=0 - Zn2+[Z=30]=[Ar]183 d10\mathrm{Zn}^{2+}[\mathrm{Z}=30]=[\mathrm{Ar}]_{18} 3 \mathrm{~d}^{10} Number of unpaired electron =0=0 ∴\therefore The correct option among the following is (4).
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