Magnetic moment of [Ti(H_2 O)_6]^ 4+ , [Mn(H_2 O)_6]^ 2+ and [Cr (H_2 O)_6]^ 3+ can be represented as X, Y and Z . They are in order of

Correct answer: A. X Z Y aligned X=[Ti & .(H_2 O)_6]^ 4+ , E · C of Ti^ 4+ =3 d^ n & =0 μ_B & =0 Y & =[Mn(H_2 O)_6]^ 2+ , E · C of Mn^ +2 =3 d^5 n & =3 μ_B & =3.87 BM Z & =[Cr(H_2 O)_6]^ 3+ , E · C of Cr^ 3+ =3 d^3 n & =3 μ_B & =3.87 BM aligned Hence, the correct order of magnetic moment of X, Y, Z is X < Z < Y

JIPMER 2016

Exam: JIPMER
Year: 2016
Subject: Chemistry
Chapter: Coordination Compounds

JIPMER 2016 · Chemistry · Coordination Compounds

Magnetic moment of [Ti(H_2 O)_6]^ 4+ , [Mn(H_2 O)_6]^ 2+ and [Cr...

Magnetic moment of

\left[\mathrm{Ti}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{4+}

, \left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} and \left[\mathrm{Cr}

\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}

can be represented as

X, Y

and

Z

. They are in order of

Options

A $X \lt Z \lt Y$
B $Z \lt Y \lt X$
C $X \lt Y \lt Z$
D $Z \lt Y \lt X$

Correct answer

A. $X \lt Z \lt Y$

Step-by-step solution

\begin{aligned} \mathrm{X}=[\mathrm{Ti} & \left.\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{4+}, \mathrm{E} \cdot \mathrm{C} \text{\text{ of } } \mathrm{Ti}^{4+}=3 d^{\circ} \\ n & =0 \\ \mu_B & =0 \\ Y & =\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}, \mathrm{E} \cdot \mathrm{C} \text{ of } \mathrm{Mn}^{+2}=3 d^5 \\ n & =3 \\ \mu_B & =3.87 \mathrm{BM} \\ \mathrm{Z} & =\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \mathrm{E} \cdot \mathrm{C} \text{ of } \mathrm{Cr}^{3+}=3 d^3 \\ n & =3 \\ \mu_B & =3.87 \mathrm{BM}\end{aligned}

Hence, the correct order of magnetic moment of

X, Y, Z

X < Z < Y

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