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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Chemistry
Chapter
Coordination Compounds

JIPMER 2010 · Chemistry · Coordination Compounds

Considering H_2 O as weak field ligand, the number of unpaired...

Considering H2O\mathrm{H}_2 \mathrm{O} as weak field ligand, the number of unpaired electrons in \left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} will be (Atomic number of Mn=25\mathrm{Mn}=25 )Considering H_2 O as weak field ligand, the number of unpaired electrons in [Mn (H_2 O)_6]^ 2+ will be (Atomic number

Options

  1. Afive
  2. Btwo
  3. Cfour
  4. Dthree

Correct answer

A. five

Step-by-step solution

Mn in [Mn(H2O)6]2+ispresentas\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} is present as\mathrm{Mn}^{2+}\left(3 d^5\right).<imgsrc="https://cdn−question−pool.getmarks.app/pyq/jipmer/of2KFryMPP9GItJY1MaBOqlYIvZNhVxvyrLiGq18l5A.original.fullsize.png"/>. <img src="https://cdn-question-pool.Quantrex.app/pyq/jipmer/of2KFryMPP9GItJY1MaBOqlYIvZNhVxvyrLiGq18l5A.original.fullsize.png"/>s p^3 d^2hybridisationoccursin[Mn(H2O)6]2+hybridisation occurs in \left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}. Due to the presence of weak field ligand pairing of electron does not take place, hence the number of unpaired electrons is five.
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