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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Physics
Chapter
Semiconductors

JIPMER 2016 · Physics · Semiconductors

The transfer ratio β of a transistor is 50 . The input resistance...

The transfer ratio β\beta of a transistor is 50 . The input resistance of the transistor when used in the common emitter configuration is 2kΩ2 \mathrm{k} \Omega. The peak value of the collector AC current for an AC input voltage of 0.02 V peak is

Options

  1. A200μA200 \mu \mathrm{A}
  2. B0.01 mA
  3. C0.25 mA
  4. D500μA500 \mu \mathrm{A}

Correct answer

D. 500μA500 \mu \mathrm{A}

Step-by-step solution

Given, β=50,R=2kΩ=2×103Ω\beta=50, R=2 \mathrm{k} \Omega=2 \times 10^3 \Omega, ΔVb=0.02 Vic=?\begin{aligned} & \Delta V_b=0.02 \mathrm{~V} \\ & i_c=?\end{aligned} Input current, ib=ΔVbRb=0.022000=10−5 Ai_b=\frac{\Delta V_b}{R_b}=\frac{0.02}{2000}=10^{-5} \mathrm{~A} Also, current gain, β=icib\beta=\frac{i_c}{i_b}∴ic=βib=50×10−5 A=500×10−6 A=500μA\begin{aligned} \therefore \quad i_c & =\beta i_b=50 \times 10^{-5} \mathrm{~A} \\ & =500 \times 10^{-6} \mathrm{~A}=500 \mu \mathrm{A}\end{aligned}$$
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