For CE configuration n-p-n transistor. Which of the following statement is correct?

Correct answer: C. I_E=I_C+I_B In CE configuration n-p-n transistor, emitter current ( I _ E ) is equal to sum of collector current ( I _ C ) and base current ( I _ B ) i.e, I_ E = I _ C + I _ B

JIPMER 2019

Exam: JIPMER
Year: 2019
Subject: Physics
Chapter: Semiconductors

JIPMER 2019 · Physics · Semiconductors

For CE configuration n-p-n transistor. Which of the following...

For CE configuration

\mathrm{n}-\mathrm{p}-\mathrm{n}

transistor. Which of the following statement is correct?

Options

A $I_C=I_E+I_B$
B $I_B=I_E+I_C$
C $I_E=I_C+I_B$
DAll of these

Correct answer

C. $I_E=I_C+I_B$

Step-by-step solution

In CE configuration

n-p-n

transistor, emitter current

\left(

\mathrm{I}

_{\mathrm{E}}\right)

is equal to sum of collector current

\left(

\mathrm{I}

_{\mathrm{C}}\right)

and base current

\left(

\mathrm{I}

_{\mathrm{B}}\right)

i.e,

\mathrm{I}_{\mathrm{E}}=

\mathrm{I}

_{\mathrm{C}}+

\mathrm{I}

_{\mathrm{B}}

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