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JIPMER 2006
Exam
JIPMER
Year
2006
Subject
Physics
Chapter
Semiconductors
JIPMER 2006 · Physics · Semiconductors
The amplification factor of a triode valve is 15 . If the grid...
The amplification factor of a triode valve is 15 . If the grid voltage is changed by 0.3 V , the change in plate voltage in order to keep the current constant (in volt) is :
Options
A
0.02
B
0.002
C
4.5
D
5.0
Correct answer
C. 4.5
Step-by-step solution
μ
=
15
,
Δ
V
g
=
0
⋅
3
∴
μ
=
Δ
V
p
Δ
V
g
⇒
Δ
V
p
=
μ
Δ
V
g
=
15
×
0.3
=
4.5
V
.
\begin{aligned} \mu=15, \Delta V_g & =0 \cdot 3 \\ \therefore \quad \mu & =\frac{\Delta V_p}{\Delta V_g} \Rightarrow \Delta V_p=\mu \Delta V_g \\ & =15 \times 0.3 \\ & =4.5 \mathrm{~V} .\end{aligned}
μ
=
15
,
Δ
V
g
∴
μ
=
0
⋅
3
=
Δ
V
g
Δ
V
p
⇒
Δ
V
p
=
μ
Δ
V
g
=
15
×
0.3
=
4.5
V
.
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