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AIIMS 2012
Exam
AIIMS
Year
2012
Subject
Chemistry
Chapter
Coordination Compounds

AIIMS 2012 · Chemistry · Coordination Compounds

Assertion : [Fe(H_2 O)_5 NO] SO_4 is paramagnetic. Reason : The Fe...

Assertion : [Fe(H2O)5NO]SO4\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4 is paramagnetic.Reason : The Fe in \left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{NO}_4 has three unpaired electrons.Assertion : [Fe(H_2 O)_5 NO] SO_4 is paramagnetic. Reason : The Fe in [Fe(H_2 O)_5 NO] NO_4 has three unpaired

Options

  1. AIf both assertion and reason are true and reason is the correct explanation of assertion
  2. BIf both assertion and reason are true but reason is not the correct explanation of assertion
  3. CIf assertion is true but reason is false
  4. DIf both assertion and reason are false.

Correct answer

A. If both assertion and reason are true and reason is the correct explanation of assertion

Step-by-step solution

(a) : Fe+:[Ar]3d64s1\mathrm{Fe}^{+}:[\mathrm{Ar}] 3 d^6 4 s^1 When the weak field ligand H2O\mathrm{H}_2 \mathrm{O} and strong field ligand NO attack, the configuration changes as follows: Fe+:[Ar]3d74s0\mathrm{Fe}^{+}:[\mathrm{Ar}] 3 d^7 4 s^0 Assertion : [Fe(H_2 O)_5 NO] SO_4 is paramagnetic. Reason : The Fe in [Fe(H_2 O)_5 NO] NO_4 has three unpaired
∴Fe+\therefore \quad \mathrm{Fe}^{+}has 3 unpaired electrons.
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