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AIIMS 2010
Exam
AIIMS
Year
2010
Subject
Chemistry
Chapter
Coordination Compounds

AIIMS 2010 · Chemistry · Coordination Compounds

A complex PtCl_4 .5 NH_3 shows a molar conductance of 402 ohm^ -1...

A complex PtCl4.5NH3\mathrm{PtCl}_4 .5 \mathrm{NH}_3 shows a molar conductance of 402ohm−1 cm2 mol−1402 \mathrm{ohm}^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1} in water and precipitates three moles of AgCl\mathrm{AgCl} with AgNO3\mathrm{AgNO}_3 solution. The formula of the complex is

Options

  1. A[Pt(NH3)6]Cl4\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_4
  2. B[Pt(NH3)4Cl2]Cl2\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}_2
  3. C[Pt(NH3)5Cl]Cl3\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_3
  4. D[Pt(NH3)3Cl3]Cl\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \mathrm{Cl}

Correct answer

C. [Pt(NH3)5Cl]Cl3\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_3

Step-by-step solution

The complex PtCl4.5NH3\mathrm{PtCl}_4 .5 \mathrm{NH}_3 is designated as \left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_3whichionizesto[Pt(NH3)5Cl]3++3Cl−which ionizes to \left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]^{3+} +3 \mathrm{Cl}^{-}ions. Thus total ions produced are four but three moles of AgCl\mathrm{AgCl} are produced from 3Cl−3 \mathrm{Cl}^{-}ions with AgNO3\mathrm{AgNO}_3.
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