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NEET 2026
Exam
NEET
Year
2026
Subject
Chemistry
Chapter
Chapter

NEET 2026 · Chemistry · Chapter

For one mole of an ideal gas, the amount of heat required to raise...

For one mole of an ideal gas, the amount of heat required to raise its temperature by 1 K1\text{ K} at constant volume is xx. The amount of heat required to raise the temperature of the same gas by 1 K1\text{ K} at constant pressure will be (where RR is the universal gas constant):

Options

  1. Ax+Rx + R
  2. Bx−Rx - R
  3. Cx+R2x + \dfrac{R}{2}
  4. Dx−R2x - \dfrac{R}{2}

Correct answer

A. x+Rx + R

Step-by-step solution

The heat required to raise the temperature of nn moles of an ideal gas by ΔT\Delta T at constant volume is given by QV=nCVΔTQ_V = n C_V \Delta T.

Given n=1 moln = 1\text{ mol} and ΔT=1 K\Delta T = 1\text{ K}, we have QV=CV=xQ_V = C_V = x.

The heat required to raise the temperature of the gas by ΔT\Delta T at constant pressure is given by QP=nCPΔTQ_P = n C_P \Delta T.

For n=1 moln = 1\text{ mol} and ΔT=1 K\Delta T = 1\text{ K}, we have QP=CPQ_P = C_P.

Using Mayer's relation for an ideal gas, CP−CV=RC_P - C_V = R.

Substituting CV=xC_V = x, we get CP=x+RC_P = x + R.

Therefore, the amount of heat required at constant pressure is x+Rx + R.

Answer: x+Rx + R
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