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JEE Main · Chemistry · Practical Chemistry
An aqueous solution of a lead(II) salt is divided into two test...
An aqueous solution of a lead(II) salt is divided into two test tubes. Addition of potassium iodide to the first test tube produces a yellow precipitate 'X' which dissolves in boiling water and recrystallizes on cooling. Addition of potassium chromate to the second test tube produces a yellow precipitate 'Y' which is insoluble in acetic acid.
The chemical identities of precipitates X and Y respectively are:
The chemical identities of precipitates X and Y respectively are:
Options
- AX = , Y =
- BX = , Y =
- CX = , Y =
- DX = , Y =
Correct answer
C. X = , Y =
Step-by-step solution
The reaction of with yields a yellow precipitate of lead iodide (). A unique characteristic of is that it dissolves in boiling water to give a colorless solution and recrystallizes as golden spangles upon cooling.
The reaction of with yields a yellow precipitate of lead chromate (), which is insoluble in acetic acid but soluble in sodium hydroxide.
Thus, X is and Y is .
Answer: X = , Y =
The reaction of with yields a yellow precipitate of lead chromate (), which is insoluble in acetic acid but soluble in sodium hydroxide.
Thus, X is and Y is .
Answer: X = , Y =