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JEE Main
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JEE Main
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Chemistry
Chapter
Solid State

JEE Main · Chemistry · Solid State

An element crystallizes in a body-centered cubic (bcc) lattice with...

An element crystallizes in a body-centered cubic (bcc) lattice with an edge length of 400400 pm. If the density of the element is 5.05.0 g cm−3^{-3}, the molar mass of the element is ________ g mol−1^{-1}.

(Nearest integer)

[Given: NA=6.0×1023N_A = 6.0 \times 10^{23} mol−1^{-1}]

Correct answer

96

Step-by-step solution

For a bcc lattice, the effective number of atoms per unit cell, Z=2Z = 2.

Edge length, a=400a = 400 pm =400×10−12= 400 \times 10^{-12} m =4×10−8= 4 \times 10^{-8} cm.

The density of the unit cell is given by:
ρ=Z×MNA×a3\rho = \dfrac{Z \times M}{N_A \times a^3}

Rearranging for molar mass MM:
M=ρ×NA×a3ZM = \dfrac{\rho \times N_A \times a^3}{Z}

Substituting the given values:
M=5.0×6.0×1023×(4×10−8)32M = \dfrac{5.0 \times 6.0 \times 10^{23} \times (4 \times 10^{-8})^3}{2}

M=30.0×1023×64×10−242M = \dfrac{30.0 \times 10^{23} \times 64 \times 10^{-24}}{2}

M=30.0×6.42=96M = \dfrac{30.0 \times 6.4}{2} = 96 g mol−1^{-1}.

Answer: 9696
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