When solid cuprous oxide ( Cu ₂ O ) is treated with dilute sulfuric acid, it undergoes disproportionation to yield a metallic precipitate and an aqueous transition metal ion. If the spin-only magnetic moment of this resulting aqueous transition metal ion is x B.M., the value of x is

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When cuprous oxide ( Cu ₂ O ) reacts with dilute sulfuric acid, the Cu ( I ) ions undergo disproportionation in the aqueous acidic medium. The reaction is: Cu ₂ O + H ₂ SO ₄ Cu + CuSO ₄ + H ₂ O The aqueous transition metal ion formed is Cu ²⁺ . The electronic configuration of Cu ²⁺ is [ Ar ] 3d^9 . Number of unpaired electrons ( n ) = 1 . The spin-only magnetic moment is given by: = n(n+2) B.M. = 1(1+2) = 3 B.M. Comparing this with x B.M., we get x = 3 . Answer: 3