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JEE MainChemistryp Block Elements (Group 13 & 14)

When BCl ₃ undergoes hydrolysis in an alkaline aqueous medium, it forms a complex anion X . Separately, when AlCl ₃ is dissolved in an acidified aqueous solution, it forms a complex cation Y . The hybridization of the central atom in complex species X and Y , respectively, are:

Options

  1. Asp ^2 and sp ^3
  2. Bsp ^3 and sp ^3 d ^2
  3. Csp ^3 and sp ^3
  4. Dsp ^3 d ^2 and sp ^3 d ^2

Correct answer

B. sp ^3 and sp ^3 d ^2

Step-by-step solution

In an alkaline aqueous medium, BCl ₃ undergoes hydrolysis to form the tetrahydroxoborate(III) ion, [ B ( OH )₄]^- . Since boron lacks d-orbitals, it restricts its maximum covalency to 4. The hybridization of boron in [ B ( OH )₄]^- is sp ^3 . In an acidified aqueous solution, AlCl ₃ forms the hexaaquaaluminium(III) ion, [ Al ( H ₂ O )₆]³⁺ . Aluminium has vacant 3d-orbitals and can expand its coordination number to 6. The hybridization of aluminium in [ Al ( H ₂ O )₆]³⁺ is sp ^3 d ^2 . Answer: sp ^3 and sp ^3 d ^2

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