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JEE Main
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Practical Chemistry

JEE Main · Chemistry · Practical Chemistry

An aqueous solution of an unknown metal salt is subjected to...

An aqueous solution of an unknown metal salt is subjected to qualitative analysis. When H2S\text{H}_2\text{S} gas is passed through the solution in the presence of dilute HCl\text{HCl}, no precipitate is observed. However, when H2S\text{H}_2\text{S} gas is passed through the same solution after making it alkaline with NH4OH\text{NH}_4\text{OH} in the presence of NH4Cl\text{NH}_4\text{Cl}, a distinct precipitate is formed. The metal cation present in the solution is:

Options

  1. ACu2+\text{Cu}^{2+}
  2. BPb2+\text{Pb}^{2+}
  3. CCo2+\text{Co}^{2+}
  4. DBa2+\text{Ba}^{2+}

Correct answer

C. Co2+\text{Co}^{2+}

Step-by-step solution

The qualitative analysis of cations relies on selective precipitation based on solubility products. Group II cations (such as Cu2+\text{Cu}^{2+} and Pb2+\text{Pb}^{2+}) precipitate as sulphides when H2S\text{H}_2\text{S} is passed in an acidic medium. Since no precipitate is formed in the acidic medium, Group II cations are absent.

Group IV cations (such as Co2+\text{Co}^{2+}, Ni2+\text{Ni}^{2+}, Mn2+\text{Mn}^{2+}, and Zn2+\text{Zn}^{2+}) require a higher concentration of sulphide ions to precipitate. This is achieved by passing H2S\text{H}_2\text{S} in an alkaline medium (using NH4OH\text{NH}_4\text{OH} and NH4Cl\text{NH}_4\text{Cl}). Since a precipitate forms under these conditions, the cation belongs to Group IV.

Among the given options, Co2+\text{Co}^{2+} is a Group IV cation. Ba2+\text{Ba}^{2+} belongs to Group V and does not precipitate as a sulphide in either medium.

Answer: Co2+\text{Co}^{2+}
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