If (x+y) (x-y) = a+b a-b , where a, b 0 and x, y are such that x and y are well-defined and non-zero, then which of the following relations is true?

Step-by-step solution

Given (x+y) (x-y) = a+b a-b Applying componendo and dividendo, we get: (x+y)+ (x-y) (x+y)- (x-y) = (a+b)+(a-b) (a+b)-(a-b) Using the sum and difference formulas for sine: 2 x y 2 x y = 2a 2b x y = a b b x = a y Answer: b x = a y