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JEE Main
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Chemistry
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Practical Chemistry

JEE Main · Chemistry · Practical Chemistry

A Group IV transition metal cation M^ 2+ reacts with...

A Group IV transition metal cation M2+\text{M}^{2+} reacts with dimethylglyoxime in an ammoniacal medium to yield a brilliant red precipitate of a complex. The hybridization and the magnetic nature of the central metal atom in this complex are respectively:

Options

  1. Asp3\text{sp}^{3}, paramagnetic
  2. Bsp3\text{sp}^{3}, diamagnetic
  3. Cdsp2\text{dsp}^{2}, paramagnetic
  4. Ddsp2\text{dsp}^{2}, diamagnetic

Correct answer

D. dsp2\text{dsp}^{2}, diamagnetic

Step-by-step solution

The formation of a brilliant red precipitate with dimethylglyoxime (DMG) in an ammoniacal medium indicates that the metal cation M2+\text{M}^{2+} is Ni2+\text{Ni}^{2+}. The complex formed is bis(dimethylglyoximato)nickel(II), [Ni(DMG)2][\text{Ni}(\text{DMG})_2].

In this complex, Nickel is in a +2+2 oxidation state with a 3d83\text{d}^{8} electronic configuration.

Although DMG is generally a weak field ligand, in this specific complex it acts as a strong field ligand due to the extra stability provided by intramolecular hydrogen bonding between the two DMG ligands. This causes the pairing of the two unpaired 3d3\text{d} electrons, leaving one inner 3d3\text{d} orbital empty.

The empty 3d3\text{d}, one 4s4\text{s}, and two 4p4\text{p} orbitals undergo dsp2\text{dsp}^{2} hybridization to form a square planar complex. Since all electrons are paired, the complex is diamagnetic.

Answer: dsp2\text{dsp}^{2}, diamagnetic
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