When 1-methylcyclopentanol is heated with concentrated H ₂ SO ₄ , it undergoes dehydration to give a major product P. The compound P is then treated with a cold, dilute aqueous solution of KMnO ₄ to yield the major product Q. The product Q

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When 1-methylcyclopentanol is heated with concentrated H ₂ SO ₄ , it undergoes dehydration to give a major product P. The compound P is then treated with a cold, dilute aqueous solution of KMnO ₄ to yield the major product Q. The product Q is:

Quantrex Academy · Accepted Answer

Correct answer: C. cis-1-Methylcyclopentane-1,2-diol

Dehydration of 1-methylcyclopentanol with concentrated H ₂ SO ₄ follows Saytzeff's rule, yielding the more substituted alkene as the major product. Thus, the major product P is 1-methylcyclopentene. Treatment of 1-methylcyclopentene with cold, dilute aqueous KMnO ₄ (Baeyer's reagent) brings about the syn-addition of two hydroxyl groups across the double bond. Because the addition is syn, the two -OH groups attach to the same face of the cyclopentane ring. This stereospecific reaction produces cis-1-methylcyclopenta

When 1-methylcyclopentanol is heated with concentrated H ₂ SO ₄ , it undergoes dehydration to give a major product P. The compound P is then treated with a cold, dilute aqueous solution of KMnO ₄ to yield the major product Q. The product Q is:

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