A synthetic polymer contains 6.2 % of phosphorus by mass. Upon analysis, it is found that 0.1 moles of this polymer contains 1.2044 10²⁴ atoms of phosphorus. The molar mass of the polymer is: (Given : Atomic mass of P is 31 u , N_A = 6.022 10²³ mol ⁻¹ )

Step-by-step solution

Number of moles of P atoms in 0.1 mol of the polymer = 1.2044 10²⁴ 6.022 10²³ = 2.0 mol Mass of P in 0.1 mol of the polymer = 2.0 mol 31 g mol ⁻¹ = 62 g Let the mass of 0.1 mol of the polymer be m . Since the polymer contains 6.2 % of phosphorus by mass: 6.2 100 m = 62 g m = 62 100 6.2 = 1000 g Mass of 0.1 mol of the polymer is 1000 g . Molar mass of the polymer (mass of 1 mole ) = 1000 g 0.1 mol = 10000 g mol ⁻¹ Answer: 10000 g mol ⁻¹