What quantity of AgCl is precipitated when one mole of...

The formula of pentaamminecarbonatocobalt(III) chloride is $[\text{Co}(\text{NH}_3)_5(\text{CO}_3)]\text{Cl}$.

In this complex, there is one ionizable chloride ion present outside the coordination sphere.

When one mole of this complex is treated with excess $\text{AgNO}_3$ solution, it yields one mole of $\text{AgCl}$ precipitate.

$[\text{Co}(\text{NH}_3)_5(\text{CO}_3)]\text{Cl} + \text{AgNO}_3 \rightarrow [\text{Co}(\text{NH}_3)_5(\text{CO}_3)]\text{NO}_3 + \text{AgCl} \downarrow$

Mass of one mole of $\text{AgCl} = 143.3 \text{ g}$.

Therefore, $143.3 \text{ g}$ of $\text{AgCl}$ is precipitated.

Answer: 143.3 g