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MHT CET 202623 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
23 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrocarbons

MHT CET 2026 · 23 April · Morning Shift · Chemistry · Hydrocarbons

Identify the products when benzene reacts with chlorine in the...

Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl3\text{AlCl}_3 respectively from the following.Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl_3Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl_3Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl_3Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl_3Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl_3Identify the products when benzene reacts with chlorine in the presence of (I) Fe and (II) anhydrous AlCl_3

Options

  1. AIn which of the following reactions H _ 2 O _ 2 acts as a reducing agent ? (a) H _ 2 O _ 2 + 2 H ^ + + 2 e ^ - → 2 H _
  2. BIn which of the following reactions H _ 2 O _ 2 acts as a reducing agent ? (a) H _ 2 O _ 2 + 2 H ^ + + 2 e ^ - → 2 H _
  3. CIn which of the following reactions H _ 2 O _ 2 acts as a reducing agent ? (a) H _ 2 O _ 2 + 2 H ^ + + 2 e ^ - → 2 H _
  4. DIn which of the following reactions H _ 2 O _ 2 acts as a reducing agent ? (a) H _ 2 O _ 2 + 2 H ^ + + 2 e ^ - → 2 H _

Correct answer

B. In which of the following reactions H _ 2 O _ 2 acts as a reducing agent ? (a) H _ 2 O _ 2 + 2 H ^ + + 2 e ^ - → 2 H _

Step-by-step solution

Benzene undergoes electrophilic aromatic substitution when it reacts with halogens in the presence of a Lewis acid catalyst.

In the first case, iron (Fe\text{Fe}) reacts with chlorine to form FeCl3\text{FeCl}_3 in situ, which acts as a Lewis acid. It facilitates the generation of the electrophile (Cl+\text{Cl}^+), leading to the formation of chlorobenzene.
C6H6+Cl2→FeC6H5Cl+HCl\text{C}_6\text{H}_6 + \text{Cl}_2 \xrightarrow{\text{Fe}} \text{C}_6\text{H}_5\text{Cl} + \text{HCl}

In the second case, anhydrous AlCl3\text{AlCl}_3 is also a Lewis acid and similarly catalyzes the electrophilic substitution of benzene with chlorine to yield chlorobenzene.
C6H6+Cl2→AlCl3C6H5Cl+HCl\text{C}_6\text{H}_6 + \text{Cl}_2 \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{Cl} + \text{HCl}

Note: Hexachlorobenzene (C6Cl6\text{C}_6\text{Cl}_6) is formed only when benzene reacts with an *excess* of chlorine in the presence of anhydrous AlCl3\text{AlCl}_3 in the dark. Since excess chlorine is not mentioned, monosubstitution is considered for both reactions.

Therefore, the product in both cases (I) and (II) is chlorobenzene.

Answer:
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