A full-wave rectifier provides a DC output voltage of 20\ V . If...

Given the DC output voltage $V_{dc} = 20\ \text{V}$ and the RMS value of the AC component $V_{ac} = 2\ \text{V}$.

The ripple factor $\gamma$ is defined as the ratio of the RMS value of the AC component to the DC component of the output voltage:

$\gamma = \dfrac{V_{ac}}{V_{dc}}$

Substituting the given values:

$\gamma = \dfrac{2}{20} = 0.1$

Expressing the ripple factor in percentage:

$\gamma = 0.1 \times 100\% = 10\%$

Answer: $10\%$