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NDA 2024
Exam
NDA
Year
2024
Subject
General Ability
Chapter
General Science

NDA 2024 · General Ability · General Science

What is the oxidation state of Vanadium in V_2 O_5 ?

What is the oxidation state of Vanadium in V2O5\mathrm{V}_2 \mathrm{O}_5 ?

Options

  1. A+2
  2. B+4
  3. C+3
  4. D+5

Correct answer

D. +5

Step-by-step solution

The oxidation state of vanadium in V2O5=+5\mathrm{V}_2 \mathrm{O}_5=+5 The oxidation state of O -atom is -2. Let, oxidation state of vanadium =x=xV2O5=02x+(−2×5)=02x−10=02x=+10x=+102=+5\begin{aligned} \mathrm{V}_2 \mathrm{O}_5 & =0 \\ 2 x+(-2 \times 5) & =0 \\ 2 x-10 & =0 \\ 2 x & =+10 \\ x & =\frac{+10}{2}=+5 \end{aligned}$$
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