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What is the oxidation state of Vanadium in V ₂ O ₅ ?

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Correct answer

D. +5

Step-by-step solution

The oxidation state of vanadium in V ₂ O ₅=+5 The oxidation state of O -atom is -2 . Let, oxidation state of vanadium =x aligned V ₂ O ₅ & =0 2 x+(-2 5) & =0 2 x-10 & =0 2 x & =+10 x & = +10 2 =+5 aligned

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