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NDA 2015
Exam
NDA
Year
2015
Subject
Mathematics
Chapter
Determinants

NDA 2015 · Mathematics · Determinants

The value of | array ccc 1 & 1 & 1 1 & 1+x & 1 1 & 1 & 1+y array |...

The value of \left|11111+x1111+y\begin{array}{ccc}1 & 1 & 1 \\ 1 & 1+x & 1 \\ 1 & 1 & 1+y\end{array}$\right| is$

Options

  1. Ax+yx+y
  2. Bx−yx-y
  3. Cxyx y
  4. D1+x+y1+x+y

Correct answer

C. xyx y

Step-by-step solution

\left|11111+x1111+y\begin{array}{ccc}1 & 1 & 1 \\ 1 & 1+\mathrm{x} & 1 \\ 1 & 1 & 1+\mathrm{y}\end{array}\right|=[(1+x)(1+y)−1]−1(1+y−1)+1(1−1−x)=1+x+y+xy−1−y−x=xy\begin{aligned} & =[(1+x)(1+y)-1]-1(1+y-1)+1(1-1-x) \\ & =1+x+y+x y-1-y-x \\ & =x y \end{aligned}∴\therefore \quad Option (C) is correct.
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