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NDA2015MathematicsDeterminantsActual

The value of | array ccc 1 & 1 & 1 1 & 1+x & 1 1 & 1 & 1+y array | is

Options

  1. Ax+y
  2. Bx-y
  3. Cx y
  4. D1+x+y

Correct answer

C. x y

Step-by-step solution

| array ccc 1 & 1 & 1 1 & 1+ x & 1 1 & 1 & 1+ y array | aligned & =[(1+x)(1+y)-1]-1(1+y-1)+1(1-1-x) & =1+x+y+x y-1-y-x & =x y aligned Option (C) is correct.

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