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NDA 2024
Exam
NDA
Year
2024
Subject
Mathematics
Chapter
Functions

NDA 2024 · Mathematics · Functions

Paragraph: Let f(x)=[x]^2- [x^2] . Question: What is...

Paragraph: Let f(x)=[x]2−[x2]f(x)=[x]^2- \left[x^2\right].
Question: What is f(0.999)+f(1.001)equalto?f(0.999)+f(1.001) equal to?

Options

  1. A−1-1
  2. B00
  3. C11
  4. D22

Correct answer

B. 00

Step-by-step solution

Given f(x)=[x]2−[x2]Accordingf(x)=[x]^2- \left[x^2\right] According to the questionf(0.999)=[0.999]^2-\left[(0.999)^2\right]=0−=0-[value lies \mathrm{b}/\mathrm{w}0 and 1 ] f(0.999)=0−0=0… (i) f(1.001)=[1.001]2−[(1.0001)2]=1−1=....(ii)\begin{aligned}& f(0.999)=0-0=0 \quad \ldots \text{ (i) }\\ & f(1.001)=[1.001]^2-\left[(1.0001)^2\right]=1-1=....(ii) \end{aligned}Adding(i)and(ii)Adding (i) and (ii)f(0.999)+f(1.001)=0-0=0
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