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Paragraph: Let f(x)=[x]^2- [x^2 ] . Question: What is f(0.999)+f(1.001) equal to?

Options

  1. A-1
  2. B0
  3. C1
  4. D2

Correct answer

B. 0

Step-by-step solution

Given f(x)=[x]^2- [x^2 ] According to the question f(0.999)=[0.999]^2- [(0.999)^2 ]=0- [value lies b / w 0 and 1 ] aligned & f(0.999)=0-0=0 (i) & f(1.001)=[1.001]^2- [(1.0001)^2 ]=1-1= ....(ii) aligned Adding (i) and (ii) f(0.999)+f(1.001)=0-0=0

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