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NDA 2021
Exam
NDA
Year
2021
Subject
Mathematics
Chapter
Functions

NDA 2021 · Mathematics · Functions

If f(x+1)=x^2-3 x+2 , then what is f(x) equal to?

If f(x+1)=x2−3x+2f(x+1)=x^2-3 x+2, then what is f(x)f(x) equal to?

Options

  1. Ax2−5x+4x^2-5 x+4
  2. Bx2−5x+6x^2-5 x+6
  3. Cx2+3x+3x^2+3 x+3
  4. Dx2−3x+1x^2-3 x+1

Correct answer

B. x2−5x+6x^2-5 x+6

Step-by-step solution

For f(x+1)=x2−3x+2=(x2+2x+1)−5x−5+6\begin{aligned} f(x+1) & =x^2-3 x+2 \\ & =\left(x^2+2 x+1\right)-5 x-5+6\end{aligned}=(x+1)2−5(x+1)+6∴f(x)=x2−5x+6\begin{aligned} & \quad=(x+1)^2-5(x+1)+6 \\ & \therefore f(x)=x^2-5 x+6\end{aligned}
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