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NDA 2018
Exam
NDA
Year
2018
Subject
Mathematics
Chapter
Functions

NDA 2018 · Mathematics · Functions

Afunction f: A arrow R is defined by the equation f(x)=x^2-4 x+5...

Afunction f:A→Rf: A \rightarrow R is defined by the equation f(x)=x2−4x+5f(x)=x^2-4 x+5 where A=(1,4)A=(1,4). What is the range of the function?

Options

  1. A(2,5)(2,5)
  2. B(1,5)(1,5)
  3. C[1,5)[1,5)
  4. D[1,5][1,5]

Correct answer

C. [1,5)[1,5)

Step-by-step solution

f(x)=x2−4x+5=(x−2)2+1f(1)=2,f(4)=5\begin{aligned} & f(x)=x^2-4 x+5=(x-2)^2+1 \\ & f(1)=2, f(4)=5\end{aligned}
∴\therefore \quad Range f(x)=[1,5)f(x)=[1,5)
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