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NDA 2016
Exam
NDA
Year
2016
Subject
Mathematics
Chapter
Functions

NDA 2016 · Mathematics · Functions

Consider the curves y=|x-1| and |x|=2 What is/are the point(s) of...

Consider the curves y=∣x−1∣\mathrm{y}=|\mathrm{x}-1| and ∣x∣=2|\mathrm{x}|=2 What is/are the point(s) of intersection of the curves?

Options

  1. A(–2, 3) only
  2. B(2,1) only
  3. C(–2, 3) and (2,1)
  4. DNeither (–2, 3) nor (2,1)

Correct answer

C. (–2, 3) and (2,1)

Step-by-step solution

\begin{gathered}y=|x-1| \text{ and }|x|=2 \\ y=\begin{cases}x-1 & x \geq 1 \\ 1-x & x < 1\end{cases}\end{gathered} and x=2x=−2\begin{aligned} \text{ and } x & =2 \\ x & =-2 \end{aligned}$HencecurvesintersectatHence curves intersect at(-2,3) and (2,1)$.
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