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NDA 2015
Exam
NDA
Year
2015
Subject
Mathematics
Chapter
Functions

NDA 2015 · Mathematics · Functions

Consider the function f(x)=(x^2-1)/(x^2+1) , where x ∈ ℝ What is...

Consider the function f(x)=x2−1x2+1f(x)=\frac{x^2-1}{x^2+1}, where x∈Rx \in \mathbb{R} What is the minimum value of f(x)f(x) ?

Options

  1. A0
  2. B12\frac{1}{2}
  3. C-1
  4. D2

Correct answer

C. -1

Step-by-step solution

f(x)f(x) is minimum at x=0∴f(0)=−11=−1∴x=0\therefore \quad \mathrm{f}(0)=\frac{-1}{1}=-1\therefore \quad minimum value of f(x)\mathrm{f}(\mathrm{x}) is -1 ∴\therefore \quad Option (C) is correct.
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