NDA2024MathematicsLimitsActual
Which one of the following is correct regarding _ x 3 |x-3| x-3 ?
Options
- ALimits exists and is equal to 1
- BLimits exists and is equal to 0
- CLimits exists and is equal to -1
- DLimit does not exist
Correct answer
D. Limit does not exist
Step-by-step solution
Given, _ x 3 |x-3| x-3 Finding LRL and RHL at x=3 LHL = lt _ x 3⁻ | x -3| x -3 = -( x -3) x -3 =-1 LHL = lt _ x 3⁺ | x -3| x -3 = ( x -3) x -3 =+1 LHL RHL, limit does not exist.