Consider the following for the two (02) items that follow: Let the...

Given $f(x) = x^2 - 1$.

The composite function $f {}^{\circ} f(x)$ is given by:

$f(f(x)) = f(x^2 - 1) = (x^2 - 1)^2 - 1$

Since $f(f(x))$ is a polynomial and continuous everywhere, the limit can be evaluated by direct substitution:

$\lim_{x \to 1} \{f {}^{\circ} f(x)\} = f(f(1))$

$f(1) = 1^2 - 1 = 0$

$f(f(1)) = f(0) = 0^2 - 1 = -1$

Thus, the limit is $-1$.

Answer: $-1$