If L is the line with DIRECTIONS ratios 3,-2,6 and passing through (1,-1,1) , then what are the coordinates of the points on L whose distance from (1,-1,1) is 2 units?

Step-by-step solution

Since equation of line is aligned & x-1 3 = y+1 -2 = z-1 6 = (let) & (x, y, z)=(3 +1,-2 -1,6 +1) aligned Now, aligned & (3 +1-1)^2+(-2 -1+1)^2+(6 +1-1)^2 =2 & = 9 ^2+4 ^2+36 ^2 =2 & 49 ^2 =2 7 =2 = 2 7 aligned So, (x, y, z)= ( 13 7 , 11 7 , 19 7 ) or ( 1 7 , -3 7 , -5 7 )