NDA2023MathematicsThree Dimensional GeometryActual
What is the equation of the sphere concentric with the sphere x^2+y^2+z^2-2 x-6 y-8 z-5=0 and which passes through the origin?
Options
- Ax^2+y^2+z^2-2 x-8 z=0
- Bx^2+y^2+z^2-2 x-6 y=0
- Cx^2+y^2+z^2-6 y-8 z=0
- Dx^2+y^2+z^2-2 x-6 y-8 z=0
Correct answer
D. x^2+y^2+z^2-2 x-6 y-8 z=0
Step-by-step solution
Since, equation of sphere concentric with the sphere x^2+y^2+z^2-2 x-6 y-8 z-5=0 is x^2+y^2+z^2-2 x-6 y-8 z+k=0 Since, (0,0,0) satisfy k=0 So, x^2+y^2+z^2-2 x-6 y-8 z=0