A plane P passes through the line of intersection of the planes 2 x - y +3 z =2, x + y - z =1 and the point (1,0,1) . If the plane P touches the sphere x^2+y^2+z^2=r^2 , then what is r equal to?

Step-by-step solution

Plane P touches the sphere x^2+y^2+z^2=r^2 then r= Distane between centre of sphere (0,0,0) to plance P . aligned & r = | 5(0)+2(0)-5 5^2+2^2+(0)^2 | & = 5 25+4 & r = 5 29 aligned