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NDA 2018
Exam
NDA
Year
2018
Subject
Mathematics
Chapter
Three Dimensional Geometry

NDA 2018 · Mathematics · Three Dimensional Geometry

The line (x-1)/(2)-(y-2)/(3)=(z-3)/(3) is given by

The line x−12−y−23=z−33isgivenby\frac{x-1}{2}-\frac{y-2}{3}=\frac{z-3}{3} is given by

Options

  1. Ax+y+z=6,x+2y−3z=−4x+y+z=6, x+2 y-3 z=-4
  2. Bx+2y−2z=−1,4x+4y−5z−3=0x+2 y-2 z=-1,4 x+4 y-5 z-3=0
  3. C3x+2y−3z=0,3x−6y+3z=−23 \mathrm{x}+2 \mathrm{y}-3 \mathrm{z}=0,3 \mathrm{x}-6 \mathrm{y}+3 \mathrm{z}=-2
  4. D3x+2y−3z=−2,3x−6y+3z=03 x+2 y-3 z=-2,3 x-6 y+3 z=0

Correct answer

D. 3x+2y−3z=−2,3x−6y+3z=03 x+2 y-3 z=-2,3 x-6 y+3 z=0

Step-by-step solution

drs of line is 2,3,42,3,4 going through option, 2(1)+3(2)+4(−2)=02(4)+3(4)−4(5)=0\begin{aligned} & 2(1)+3(2)+4(-2)=0 \\ & 2(4)+3(4)-4(5)=0 \end{aligned}
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