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NDA 2013
Exam
NDA
Year
2013
Subject
Mathematics
Chapter
Three Dimensional Geometry

NDA 2013 · Mathematics · Three Dimensional Geometry

What is the distance between the planes x-2 y+z-1=0 and -3 x+6 y-3...

What is the distance between the planes x−2y+z−1=0x-2 y+z-1=0 and −3x+6y−3z+2=0-3 x+6 y-3 z+2=0 ?

Options

  1. A33 unit
  2. B11 unit
  3. C00
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

x−2y+z=1…x-2 y+z=1\ldots (i) x−2y+z=23x-2 y+z=\frac{2}{3}\ldots(ii) Distance =∣1−231+4+1∣=136=\left|\frac{1-\frac{2}{3}}{\sqrt{1+4+1}}\right|=\frac{1}{3 \sqrt{6}}
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