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NDA 2010
Exam
NDA
Year
2010
Subject
Mathematics
Chapter
Three Dimensional Geometry

NDA 2010 · Mathematics · Three Dimensional Geometry

The vertices of a cube are (0,0,0),(2,0,0),(0,2,0) ,...

The vertices of a cube are (0,0,0),(2,0,0),(0,2,0)(0,0,0),(2,0,0),(0,2,0), (0,0,2),(2,2,0),(2,0,2),(0,2,2),(2,2,2)(0,0,2),(2,2,0),(2,0,2),(0,2,2),(2,2,2) respectively. What is the angle between any two diagonals of the cube?

Options

  1. Acos⁡−1(1/2)\cos ^{-1}(1 / 2)
  2. Bcos⁡−1(1/3)\cos ^{-1}(1 / 3)
  3. Ccos⁡−1(1/3)\cos ^{-1}(1 / \sqrt{3})
  4. Dcos⁡−1(2/3)\cos ^{-1}(2 / \sqrt{3})

Correct answer

A. cos⁡−1(1/2)\cos ^{-1}(1 / 2)

Step-by-step solution

The correct answer is option (A).
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