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Let p= 1 3 - 3 x x and q=1-3 ^2 x, 0 x , x 2 . For how many values of x does 1 p become zero?

Options

  1. ANo value
  2. BOnly one value
  3. COnly two values
  4. DOnly three values

Correct answer

C. Only two values

Step-by-step solution

Since, 1 P =0 3 (1-3 ^2 x ) -8 =0 x= 1 3 So, there are two values of x .

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