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NDA 2022
Exam
NDA
Year
2022
Subject
Mathematics
Chapter
Trigonometric Ratios & Identities

NDA 2022 · Mathematics · Trigonometric Ratios & Identities

If α+β=(π)/(4) and 2 α=1 , then what is 2 β equal to?

If α+β=π4\alpha+\beta=\frac{\pi}{4} and 2tan⁡α=12 \tan \alpha=1, then what is tan⁡2β\tan 2 \beta equal to?

Options

  1. A13\frac{1}{3}
  2. B23\frac{2}{3}
  3. C34\frac{3}{4}
  4. D35\frac{3}{5}

Correct answer

C. 34\frac{3}{4}

Step-by-step solution

∵2tan⁡α=1⇒2tan⁡α=12α+β=π4⇒tan⁡(α+β)=tan⁡π4\begin{aligned} & \because \quad 2 \tan \alpha=1 \quad \Rightarrow 2 \tan \alpha=\frac{1}{2} \\ & \alpha+\beta=\frac{\pi}{4} \quad \Rightarrow \quad \tan (\alpha+\beta)=\tan \frac{\pi}{4}\end{aligned}\Rightarrow \frac{\tan \alpha+\tan \beta}{1-\tan \alpha \cdot \tan \beta}=1\Rightarrow \tan \alpha+\tan \beta=1-\tan \alpha \cdot \tan \beta⇒12+tan⁡β=1−12⋅tan⁡β⇒1+2tan⁡β=2−tan⁡βtan⁡β=13\begin{aligned} \Rightarrow & \frac{1}{2}+\tan \beta=1-\frac{1}{2} \cdot \tan \beta \\ \Rightarrow & 1+2 \tan \beta=2-\tan \beta \\ & \tan \beta=\frac{1}{3}\end{aligned}Now,Now,\tan 2 \beta=\frac{2 \tan \beta}{1-\tan ^2 \beta}=\frac{2 \times \frac{1}{3}}{1-\frac{1}{9}}=\frac{2}{3} \times \frac{9}{8}=\frac{3}{4}$
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