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NDA 2020
Exam
NDA
Year
2020
Subject
Mathematics
Chapter
Trigonometric Ratios & Identities

NDA 2020 · Mathematics · Trigonometric Ratios & Identities

Paragraph: Read the following information and answer: Let ( 3 A)/(...

Paragraph: Read the following information and answer: Let tan⁡3Atan⁡A=K\frac{\tan 3 A}{\tan A}=K, where tan⁡A≠0\tan A \neq 0 and K≠13K \neq \frac{1}{3}.
Question: For real values of tan⁡A,K\tan A, K cannot lie between

Options

  1. A16\frac{1}{6} and 5
  2. B12\frac{1}{2} and 2
  3. C15\frac{1}{5} and 5
  4. D17\frac{1}{7} and 7

Correct answer

B. 12\frac{1}{2} and 2

Step-by-step solution

tan⁡A=(K−3)(3K−1)\tan A=\sqrt{\frac{(K-3)}{(3 K-1)}} For real value of tan⁡A,(K−33K−1)>0\tan A,\left(\frac{K-3}{3 K-1}\right) > 0. ∴\therefore For, 13<K<3\frac{1}{3} < K < 3. tan⁡A\tan \mathrm{A} is not real. Also, for 12<k<2\frac{1}{2} < \mathrm{k} < 2, tan⁡A\tan \mathrm{A} is not real.
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