NDA 2020
- Exam
- NDA
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Trigonometric Ratios & Identities
NDA 2020 · Mathematics · Trigonometric Ratios & Identities
What is 3 x+ 3 x+4 ^3 x-3 x+3 x-4 ^3 x equal to ?
What is
sin3x+cos3x+4sin3x−3sinx+3cosx−4cos3x
equal to ?
Options
- A0
- B1
- C2sin2x
- D4cos4x
Step-by-step solution
sin3x+cos3x+4sin3x−3sinx+3cosx−4cos3x=sin3x+cos3x−sin3x−cos3x=0
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