NDA 2020
- Exam
- NDA
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Trigonometric Ratios & Identities
NDA 2020 · Mathematics · Trigonometric Ratios & Identities
What is the minimum value of 3 (A+(π)/(3)) where A ∈ R ?
What is the minimum value of where ?
Options
- A-3
- B-1
- C0
- D3
Correct answer
A. -3
Step-by-step solution
Let y=3 \cdot \cos \left( A+\frac{\pi}{3}\right), y^{\prime}=-3 \cdot \sin \left( A+\frac{\pi}{3}\right) For extremum value, y^{\ prime}=0\begin{\text{ aligned }}
& \sin \left( A+\frac{\pi}{3}\right)=0 \Rightarrow A+\frac{\pi}{3}=0 \Rightarrow A=-\frac{\pi}{3}\\
& y^{\prime \prime}=-3\cdot \cos \left(A+\frac{\pi}{3}\right)\\
& \quad=-3 \cos \left(-\frac{\pi}{3}+\frac{\pi}{3}\right)=-3 \cos (0)=-3
\end{aligned}