NDA 2017
- Exam
- NDA
- Year
- 2017
- Subject
- Mathematics
- Chapter
- Trigonometric Ratios & Identities
NDA 2017 · Mathematics · Trigonometric Ratios & Identities
If (α+β)=2 and (α-β)=1 , then (2 α) is equal to
If
tan(α+β)=2 and
tan(α−β)=1, then
tan(2α) is equal to
Step-by-step solution
tan(α+β)=2tan(α−β)=1tan2α=tan[(α+β)+(α−β)]=1−tan(α+β)⋅tan(α−β)tan(α+β)+tan(α−β)=1−2.12+1=−13=−3
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