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NDA 2015
Exam
NDA
Year
2015
Subject
Mathematics
Chapter
Trigonometric Ratios & Identities

NDA 2015 · Mathematics · Trigonometric Ratios & Identities

Let θ be a positive angle. If the number of degrees in θ is divided...

Let θ\theta be a positive angle. If the number of degrees in θ\theta is divided by the number of radians in θ\theta, then an irrational number 180π\frac{180}{\pi} results. If the number of degrees in θ\theta is multiplied by the number of radians in θ\theta, then an irrational number 125π9\frac{125 \pi}{9} results. The angle θ\theta must be equal to

Options

  1. A30∘30^{{}^{\circ}}
  2. B45∘45^{{}^{\circ}}
  3. C50∘50^{{}^{\circ}}
  4. D60∘60^{{}^{\circ}}

Correct answer

C. 50∘50^{{}^{\circ}}

Step-by-step solution

From going by the options, option (A), θ=30∘\theta=30^{{}^{\circ}}, as we know that 180∘=π180^{{}^{\circ}}=\pi radian ∴30∘=30π180\therefore \quad 30^{{}^{\circ}}=\frac{30 \pi}{180} radian Now according to question, 30∘×180∘30∘π=180π\frac{30^{{}^{\circ}} \times 180^{{}^{\circ}}}{30^{{}^{\circ}} \pi}=\frac{180}{\pi} Now number of degree in θ\theta is multiplied by number of radians in θ\theta. ∴30∘×30π180=900π180=10π2=5π≠125π9\therefore \quad 30^{{}^{\circ}} \times \frac{30 \pi}{180}=\frac{900 \pi}{180}=\frac{10 \pi}{2}=5 \pi \neq \frac{125 \pi}{9} From option (B), θ=45∘∴45∘=45∘π180 radian \begin{aligned} & \theta=45^{{}^{\circ}} \\ \therefore \quad & 45^{{}^{\circ}}=\frac{45^{{}^{\circ}} \pi}{180} \text{ radian }\end{aligned} Now according to question, 45∘×18045∘π=180π\frac{45^{{}^{\circ}} \times 180}{45^{{}^{\circ}} \pi}=\frac{180}{\pi} Now number of degree in θ\theta is multiplied by number of radian in θ\theta. ∴45∘×45∘π180∘=45π4≠125π9\therefore \quad 45^{{}^{\circ}} \times \frac{45^{{}^{\circ}} \pi}{180^{{}^{\circ}}}=\frac{45 \pi}{4} \neq \frac{125 \pi}{9} From option (C), θ=50∘\theta=50^{{}^{\circ}} As we know that 180∘=π180^{{}^{\circ}}=\pi radian ∴50∘=50π180\therefore \quad 50^{{}^{\circ}}=\frac{50 \pi}{180} radian Now according to question 50∘×180∘50∘π=180π\frac{50^{{}^{\circ}} \times 180^{{}^{\circ}}}{50^{{}^{\circ}} \pi}=\frac{180}{\pi} Now number of degree in ' θ\theta ' is multiplied by number of radian in θ\theta. ∴50∘×50π180=2500π180=125π9∴\therefore \quad 50^{{}^{\circ}} \times \frac{50 \pi}{180}=\frac{2500 \pi}{180}=\frac{125 \pi}{9}\therefore \quad Option (C) is correct.
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