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NEET 2026
Exam
NEET
Year
2026
Subject
Chemistry
Chapter
Coordination Compounds

NEET 2026 · Chemistry · Coordination Compounds

Match List I with List II : List I (Complex/ion) List II...

Match List I with List II :
List I (Complex/ion)List II (Shape/geometry)
A. [Pt(Cl2)(NH3)2][\text{Pt}(\text{Cl}_2)(\text{NH}_3)_2]I. Octahedral
B. [Co(NH3)6]Cl3[\text{Co}(\text{NH}_3)_6]\text{Cl}_3II. Trigonal bipyramidal
C. [NiCl4]2−[\text{NiCl}_4]^{2-}III. Square planar
D. [Fe(CO)5][\text{Fe}(\text{CO})_5]IV. Tetrahedral

Choose the correct answer from the options given below :

Options

  1. AA-III, B-IV, C-I, D-II
  2. BA-III, B-I, C-IV, D-II
  3. CA-IV, B-I, C-III, D-II
  4. DA-I, B-III, C-IV, D-II

Correct answer

B. A-III, B-I, C-IV, D-II

Step-by-step solution

For [Pt(Cl2)(NH3)2][\text{Pt}(\text{Cl}_2)(\text{NH}_3)_2], Pt is in +2+2 oxidation state. Pt(II) complexes are generally square planar with dsp2dsp^2 hybridization.

For [Co(NH3)6]Cl3[\text{Co}(\text{NH}_3)_6]\text{Cl}_3, Co is in +3+3 oxidation state. With a coordination number of 6, it forms an octahedral geometry.

For [NiCl4]2−[\text{NiCl}_4]^{2-}, Ni is in +2+2 oxidation state (3d83d^8). Since Cl−\text{Cl}^- is a weak field ligand, no pairing of electrons occurs, resulting in sp3sp^3 hybridization and a tetrahedral geometry.

For [Fe(CO)5][\text{Fe}(\text{CO})_5], Fe is in 00 oxidation state. With a coordination number of 5, it forms a trigonal bipyramidal geometry with dsp3dsp^3 hybridization.

Therefore, the correct matching is A →\rightarrow III, B →\rightarrow I, C →\rightarrow IV, D →\rightarrow II.

Answer: A-III, B-I, C-IV, D-II
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