Given below are two statements : Statement I: Both [Co(NH_3)_6]^ 3+...

In $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}, \mathrm{Co}^{3+}$ ion is having $3 \mathrm{~d}^6$ configuration. Electronic configuration of $\mathrm{Co}^{3+}$ :
In presence of $\mathrm{NH}_3$ ligand, pairing of electrons takes place and it becomes diamagnetic complex ion. In presence of $\mathrm{NH}_3$ ligand :
$\therefore \quad$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+} is octahedral with $\mathrm{d}^2 \mathrm{sp}^3$ hybridisation and it is diamagnetic in nature. In case of \left[\mathrm{CoF}_6\right]^{3-}$, Co is in +3 oxidation state and it is having$3 \mathrm{~d}^6$configuration. In presence of weak field$\mathrm{F}^{-}$ligand, pairing does not take place. In presence of$\mathrm{F}^{-}$ligands :<img src="https://cdn-question-pool.Quantrex.app/pyq/neet/d6OJC9jfmBSfiFyR1rxrh_NcWdwlW3-x_yOHbGg4AMo.original.fullsize.png"/><br/>$\therefore$In \left[\mathrm{CoF}_6\right]^{3-}, \mathrm{Co}^{3+}$ is $\mathrm{sp}^3 \mathrm{~d}^2$ hybridised with four unpaired electrons, so it is paramagnetic in nature.