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NEET 2019
Exam
NEET
Year
2019
Subject
Chemistry
Chapter
Coordination Compounds

NEET 2019 · Chemistry · Coordination Compounds

Aluminium chloride in acidified aqueous solution forms a complex '...

Aluminium chloride in acidified aqueous solution forms a complex ' AA ', in which hybridisation state of Al\mathrm{Al} is ' B\mathrm{B} '. What are ' A\mathrm{A} ' and ' B\mathrm{B} ', respectively?Aluminium chloride in acidified aqueous solution forms a complex ' A ', in which hybridisation state of Al is ' B '.Aluminium chloride in acidified aqueous solution forms a complex ' A ', in which hybridisation state of Al is ' B '.

Options

  1. A[Al(H2O)6]3+,sp3d2\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \mathrm{sp}^3 d^2
  2. B[Al(H2O)4]3+,sp3\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{3+}, s p^3
  3. C[Al(H2O)4]3+,dsp2\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{3+}, d s p^2
  4. D[Al(H2O)6]3+,d2sp3\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, d^2 s p^3

Correct answer

A. [Al(H2O)6]3+,sp3d2\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \mathrm{sp}^3 d^2

Step-by-step solution

Aluminium chloride in acidified aqueous solution forms an octahedral complex. Aqueous solution is mostly water and when the compound is dissolved in acidified aqueous solution, the water fills its vacancies and an octahedral complex, ' A′\mathrm{A}^{\prime} which is \left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+} is formed. Aluminium chloride in acidified aqueous solution forms a complex ' A ', in which hybridisation state of Al is ' B '.
Aluminium chloride in acidified aqueous solution forms a complex ' A ', in which hybridisation state of Al is ' B '.
Thus, the hybridisation state of Al\mathrm{Al} in \left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+} is sp3 d2( B)\mathrm{sp}^3 \mathrm{~d}^2(\mathrm{~B}).
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